(x^2+x-2)/(x^2+4x+3)*(3x+9)/(x-1)

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Solution for (x^2+x-2)/(x^2+4x+3)*(3x+9)/(x-1) equation: 


D( x )

x^2+4*x+3 = 0

x-1 = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

DELTA = 4^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-4)/(1*2) or x = (-4^(1/2)-4)/(1*2)

x = -1 or x = -3

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-3) U (-3:-1) U (-1:1) U (1:+oo)

(((x^2+x-2)/(x^2+4*x+3))*(3*x+9))/(x-1) = 0

((x^2+x-2)*(3*x+9))/((x^2+4*x+3)*(x-1)) = 0

x^2+x-2 = 0

x^2+x-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-1)/(1*2) or x = (-9^(1/2)-1)/(1*2)

x = 1 or x = -2

(x+2)*(x-1) = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

DELTA = 4^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-4)/(1*2) or x = (-4^(1/2)-4)/(1*2)

x = -1 or x = -3

(x+3)*(x+1) = 0

((x+2)*(3*x+9))/((x+3)*(x+1)) = 0

( 3*x+9 )

3*x+9 = 0 // - 9

3*x = -9 // : 3

x = -9/3

x = -3

( x+2 )

x+2 = 0 // - 2

x = -2

x in { -3} 

x = -2

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